find the altitude of a triangle if it hypotenuse is 25cm and one side is 15cm. About the author Quinn
Aɴsᴡᴇʀ⤵️ ʜʏᴘᴏᴛᴇɴᴜsᴇ = 25ᴄᴍ Oɴᴇ sɪᴅᴇ (ʙᴀsᴇ) = 15ᴄᴍ Fɪɴᴅ Aʟᴛɪᴛᴜᴅᴇ ᴏғ ᴀ ᴛʀɪᴀɴɢʟᴇ. (ᴀʟᴛɪᴛᴜᴅᴇ)^2 = (ʜʏᴘᴏᴛᴇɴᴜsᴇ)^2 – (ʙᴀsᴇ)^2 (Aʟᴛɪᴛᴜᴅᴇ)^2 = (25)^2 – (15)^2 (ᴀʟᴛɪᴛᴜᴅᴇ)^2 = 625 – 225 (ᴀʟᴛɪᴛᴜᴅᴇ)^2 = 400 Aʟᴛɪᴛᴜᴅᴇ = ✓400 ᴀʟᴛɪᴛᴜᴅᴇ = 20ᴄᴍ Aʟʟ ᴛʜᴇ ʙᴇsᴛ 🙂 Reply
[tex] {al}^{2} = {h}^{2} – {b}^{2} [/tex] [tex] = \sqrt{ {25}^{2} – {15}^{2} } = \sqrt{625 – 225} = \sqrt{400} = 20[/tex] Reply
Aɴsᴡᴇʀ⤵️
ʜʏᴘᴏᴛᴇɴᴜsᴇ = 25ᴄᴍ
Oɴᴇ sɪᴅᴇ (ʙᴀsᴇ) = 15ᴄᴍ
Fɪɴᴅ Aʟᴛɪᴛᴜᴅᴇ ᴏғ ᴀ ᴛʀɪᴀɴɢʟᴇ.
(ᴀʟᴛɪᴛᴜᴅᴇ)^2 = (ʜʏᴘᴏᴛᴇɴᴜsᴇ)^2 – (ʙᴀsᴇ)^2
(Aʟᴛɪᴛᴜᴅᴇ)^2 = (25)^2 – (15)^2
(ᴀʟᴛɪᴛᴜᴅᴇ)^2 = 625 – 225
(ᴀʟᴛɪᴛᴜᴅᴇ)^2 = 400
Aʟᴛɪᴛᴜᴅᴇ = ✓400
ᴀʟᴛɪᴛᴜᴅᴇ = 20ᴄᴍ
Aʟʟ ᴛʜᴇ ʙᴇsᴛ 🙂
[tex] {al}^{2} = {h}^{2} – {b}^{2} [/tex]
[tex] = \sqrt{ {25}^{2} – {15}^{2} } = \sqrt{625 – 225} = \sqrt{400} = 20[/tex]