Find the 10th term of the geometric sequence whose common ratio is 2/3 and whose first term is 7?

Question

Katherine · Answer

Answer:   let the common ratio and first term be r and a  therefore, r=2/3 and a=7  now 10th term of the geometric series can be written as ,  =ar^9  = 7 * (2/3)^9

Mia

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1. 1100 + 1011

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3. 11111 + 1010

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