find relation between x and y such that (x,y) is eqvidistant from points (7,1) (3,5) About the author Ayla
Let P(x,y) be equidistant from the points A(7,1) and B(3,5). AP=BP AP 2 =BP 2 (x−7) 2 +(y−1) 2 =(x−3) 2 +(y−5) 2 x 2 −14x+49+y 2 −2y+1=x 2 −6x+9+y 2 −10y+25 x−y=2 Reply
Let P(x,y) be equidistant from the points A(7,1) and B(3,5).
AP=BP
AP
2
=BP
2
(x−7)
2
+(y−1)
2
=(x−3)
2
+(y−5)
2
x
2
−14x+49+y
2
−2y+1=x
2
−6x+9+y
2
−10y+25
x−y=2