Find Perimeter of a square, whose area is
[tex] {121cm}^{2} [/tex]




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2 thoughts on “Find Perimeter of a square, whose area is <br />[tex] {121cm}^{2} [/tex]<br /><br /><br /><br /><br />​”

1. [tex] \star \: \large\underline\mathtt{given : }[/tex]

   [tex] \sf{area \: of \: square \: = 121 \: cm {}^{2} }[/tex]

   [tex] \large\underline{ \star \: \mathtt{solution : }}[/tex]

   [tex] \sf{area \: of \: square = side {}^{2} } \\ \sf{side {}^{2} = 121 \: cm {}^{2} } \\ \sf{side = \sqrt{121cm {}^{2} } } \\ \underline{\sf{side = 11cm}}[/tex]

   [tex] \sf{perimeter \: of \: square \: = 4 \times side} \\ \sf{ = 4 \times 11 \: cm} \\ \sf{ = 44 \: cm} \\ \boxed{\sf{perimeter \: of \: square \: = 44cm}}[/tex]

   hope it helps =)

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2. Step-by-step explanation:

   a² =121

   a=11 cm

   so the perimeter is 4a

   4×11 = 44 cm

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