Find P(0), P (1) and P(-2) for the following polynomials:-(i) P(x) = 10x – 4x²-3(ii) P(y) = (y + 2) (y-2) About the author Eliza
Step-by-step explanation: (I) P(x) = 10x – 4x² – 3 P(0) = 10(0) – 4(0)² – 3 = -3 P(1) = 10(1) – 4(1)² – 3 = 10 – 4 – 3 = 10 – 7 = 3 P(-2) = 10(-2) – 4(-2)² – 3 = -20 – 4(4) – 3 = -20 -16 -3 = -20-19 = -39 (II) P(y) = ( y + 2 )( y – 2 ) P(0) = ( 0 + 2 )( 0 – 2 ) = 2 × (-2) = -4 P(1) = ( 1 + 2 )( 1 – 2 ) = 3(-1) = -3 P(-2) = ( -2+2 )( -2-2 ) = 0(-4) = 0 Thank you pls mark as brainly be safe Reply
Step-by-step explanation:
(I) P(x) = 10x – 4x² – 3
P(0) = 10(0) – 4(0)² – 3 = -3
P(1) = 10(1) – 4(1)² – 3 = 10 – 4 – 3 = 10 – 7 = 3
P(-2) = 10(-2) – 4(-2)² – 3 = -20 – 4(4) – 3
= -20 -16 -3 = -20-19 = -39
(II) P(y) = ( y + 2 )( y – 2 )
P(0) = ( 0 + 2 )( 0 – 2 ) = 2 × (-2) = -4
P(1) = ( 1 + 2 )( 1 – 2 ) = 3(-1) = -3
P(-2) = ( -2+2 )( -2-2 ) = 0(-4) = 0
Thank you
pls mark as brainly
be safe