Find p(0),p(1) and p(2) for each of the following polynomial
p(y)=y2-y+1​

2 thoughts on “Find p(0),p(1) and p(2) for each of the following polynomial <br />p(y)=y2-y+1​”

1. Answer:

   hope it helps you

   have a great day

   Reply

2. Answer:(i) p(y)=y

   2
   

   −y+1
   

   p(0)=(0)

   2
   

   −(0)+1=0+0+1=1
   

   p(1)=(1)

   2
   

   −(1)+1=1−1+1=1
   

   p(2)=(2)

   2
   

   −(2)+1=4−2+1=3
   

   
   

   (ii) p(t)=2+t+2t

   2
   

   −t

   3
   

   p(0)=2+(0)+2(0)

   2
   

   −t

   3
   

   =2+0+0−0=2
   

   p(1)=2+(1)+2(2)

   2
   

   −(1)

   3
   

   =2+1+2−1=4
   

   p(2)=2+(2)+2(2)

   2
   

   −(2)

   3
   

   =2+2+8−8=4
   

   
   

   (iii) p(x)=x

   3
   

   p(0)=(0)

   3
   

   =0
   

   p(1)=(1)

   3
   

   =1
   

   p(2)=(2)

   3
   

   =8
   

   
   

   (iv) p(x)=(x−1)(x+1)
   

   p(0)=(0−1)(0+1)=(−1)(1)=−1
   

   p(1)=(1−1)(1+1)=(0)(2)=0
   

   p(2)=(2−1)(2+1)=(1)(3)=3

   Step-by-step explanation:please mark me brainlist????

   Reply