Find out the nth Term and 12th term of the series
3/5,1/5, (-)1/5,(-)3/5
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2 thoughts on “Find out the nth Term and 12th term of the series <br />3/5,1/5, (-)1/5,(-)3/5<br />​”

1. Step-by-step explanation:

   d = t2-t1 = 1/5-3/5 = -2/5

   = t3-t2 = -1/5-1/5 = -2/5

   3/5,1/5, (-)1/5,(-)3/5. A. P.

   a = 3/5. d = -2/5

   an = a+(n-1)d

   a12 = a+11d

   = 3/5-22/5 = -19/5

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2. Answer:

   Step-by-step explanation:

   here,a=3/5,d=1/5-3/5=-2/5

   nth term(tn)=a+(n-1)d

   =3/5+(-2n/5+2/5) [d= -2/5]

   =1-2n/5

   and T12=3/5+(12-1)-2/5

   =3/5+11×-2/5= -19/5

   is thecorrect answer .

   mark me as brainliest..

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