find M and N so that the following number is divisible by both 3 and 5. a) M56N, b) 45M7N, c) N608M About the author Eden
Step-by-step explanation: for division by 5 a) N = 0,5 for N=0 M+5+6+0= multiple of 3 11+M= multiple of 3 M is a digit having value from 0 to 9 11+M has value from 11 to 20 11+M=12,15,18 M =1,4,7 for N=5 M+5+6+5= mutiple of 3 M+16=mutiple of 3 M+16 has value from 16 to 25 M+16=18,21,24 M=2,5,8 b) N=0,5 for divisibility by 5 N=0 M+4+5+7+0=multiple of 3 M+16= multiple of 3 M+16 has value from 16 to 25 M+16=18,21,24 M=2,5,8 for N=5 M+4+5+7+5= multiple of 3 M+21= multiple of 3 M+21 has value from 21 to 30 M+21=21,24,27,30 M=0,3,6,9 c) M=0,5 for M=0 N+6+0+8+0= multiple of 3 N+14=multiple of 3 N+14 has value from 14 to 23 N+14=15 ,18,21 N=1,4,7 for M=5 N+6+0+8+5= multiple of 3 N+19= multiple of 3 N+19 has value from 19 to 28 N+19 =21,24,27 N=2,5,8 Reply
Answer:
A)m=2,n=5
B)m=2,n=0
C)m=2,n=5
Step-by-step explanation:
Step-by-step explanation:
for division by 5
a) N = 0,5
for N=0
M+5+6+0= multiple of 3
11+M= multiple of 3
M is a digit having value from 0 to 9
11+M has value from 11 to 20
11+M=12,15,18
M =1,4,7
for N=5
M+5+6+5= mutiple of 3
M+16=mutiple of 3
M+16 has value from 16 to 25
M+16=18,21,24
M=2,5,8
b)
N=0,5 for divisibility by 5
N=0
M+4+5+7+0=multiple of 3
M+16= multiple of 3
M+16 has value from 16 to 25
M+16=18,21,24
M=2,5,8
for N=5
M+4+5+7+5= multiple of 3
M+21= multiple of 3
M+21 has value from 21 to 30
M+21=21,24,27,30
M=0,3,6,9
c)
M=0,5
for M=0
N+6+0+8+0= multiple of 3
N+14=multiple of 3
N+14 has value from 14 to 23
N+14=15 ,18,21
N=1,4,7
for M=5
N+6+0+8+5= multiple of 3
N+19= multiple of 3
N+19 has value from 19 to 28
N+19 =21,24,27
N=2,5,8