Find
dy dx /
of the folloings:
[tex]y=sech(e^{2x)[/tex]
[tex]y=cosh^{-1} (sinh^{-1} x)[/tex]

1 thought on “Find<br /> dy dx /<br /> of the folloings: <br /> [tex]y=sech(e^{2x)[/tex]<br /> [tex]y=cosh^{-1} (sinh^{-1} x)[/tex]”

1. [tex]\frac{dy}{dx} = \frac{d(f(g(x)))}{dx} = f'(g(x)).g(x)[/tex]

   i) y = f(g(x)) = sec([tex]e^{2x}[/tex])

   [tex]\frac{dy}{dx} = \frac{d(f(g(x)))}{dx} = sec(e^{2x})tan( e^{2x}).2e^{2x}[/tex]

   ii) y = f(g(x)) = [tex]cos^{-1}(sin^{-1}(x))[/tex]

   [tex]\frac{dy}{dx} = \frac{d(f(g(x)))}{dx} = \frac{-1}{\sqrt{1 – (sin^{-1}x})^2}\frac{1}{\sqrt{1-x^2} }[/tex]

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