find centroid of triangle whose vertices are (3,4) (-7,-2) and(10,-5)​

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1. Answer:

   Given, vertices of triangle (3,4) (-7,-2) and(10,-5)

   We know Centroid of triangle is given by :

   C(x,y) = [ ( x1+x2+x3 )/3 , ( y1+y2+y3 )/3 ]

   => C(x,y) = [ ( 3+(-7)+10 )/3 , ( 4+(-2)+(-5) )/3 ]

   = [ ( 3-7+10 )/3 , ( 4-2-5 )/3 ]

   = [ 6/3 , -3/3 ]

   C( x , y ) = ( 2 , -1 )

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