Find breadth of the rectangle whose length is 40cm and diagonal is 50 cm​

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1. Answer:

   [tex]by \: pythagoras \: theorem \\ = {a}^{2} + {b}^{2} = {c}^{2} \\ {40}^{2} + {b}^{2} = {50}^{2} \\ 1600 + {b}^{2} = 2500 \\ {b}^{2} = 2500 – 1600 \\ {b}^{2} = 900 \\ b = \sqrt{900} \\ b = 30[/tex]

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