find alpha and beta are zeros of polynomial x square – 2 x minus 3 then Alpha minus beta is About the author Mackenzie
Given:- [tex] {x}^{2} – 2x – 3[/tex] on factorizing we get [tex] {x}^{2} – 3x + x – 3 \\ so \: we \: get \\ x(x – 3) + 1(x – 3) \\ [/tex] [tex]so \: the \: next \: step \: is \: [/tex] (x+1) (x-3) x+1 =0, x-3 =0 So x= -1 and x= 3 so -1 and 3 are zeros of polynomial lets take [tex] \alpha = – 1 \: and \: \beta \: = 3[/tex] so, [tex] \alpha – \beta = – 1 – ( + 3) \\ = – 1 – 3 \\ = – 4[/tex] Hope you understand thank you Reply
Answer:
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Step-by-step explanation:
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Given:-
[tex] {x}^{2} – 2x – 3[/tex]
on factorizing we get
[tex] {x}^{2} – 3x + x – 3 \\ so \: we \: get \\ x(x – 3) + 1(x – 3) \\ [/tex]
[tex]so \: the \: next \: step \: is \: [/tex]
(x+1) (x-3)
x+1 =0, x-3 =0
So x= -1 and x= 3
so -1 and 3 are zeros of polynomial
lets take
[tex] \alpha = – 1 \: and \: \beta \: = 3[/tex]
so,
[tex] \alpha – \beta = – 1 – ( + 3) \\ = – 1 – 3 \\ = – 4[/tex]
Hope you understand thank you