Find 2 consecutive integers such that two-fifth of the smaller exceeds two- ninth of the grater by 4​

By Cora

Find 2 consecutive integers such that two-fifth of the smaller exceeds two- ninth of the grater by 4​

About the author
Cora

2 thoughts on “Find 2 consecutive integers such that two-fifth of the smaller exceeds two- ninth of the grater by 4​”

  1. Step-by-step explanation:

    \large{ \bold{ \color{blue}{ \underline{Question : – }}}}

    Question:−

    Find two consecutive odd integers such that two – fifth of the smaller exceeds two – ninth of the greater by 4.

    \large{ \bold{ \color{blue}{ \underline{ \color{blue}{Solution : – }}}}}

    Solution:−

    Let the smaller odd integer be x and greater odd integer be ( X + 2 )

    \begin{gathered} \frac{2}{5} \\ \end{gathered}

    5

    2

    of smaller exceedo \begin{gathered} \frac{2}{5th} \\ \end{gathered}

    5th

    2

    of greater odd by 4.

    \begin{gathered} = > \frac{2x}{5} = \frac{2}{5}(x + 2) + 4 \\ \end{gathered}

    =>

    5

    2x

    =

    5

    2

    (x+2)+4

    \begin{gathered} = > \frac{2x}{5} = \frac{2x + 4 + 36}{9} \\ \end{gathered}

    =>

    5

    2x

    =

    9

    2x+4+36

    = > 18x \: = 5(2x + 40)=>18x=5(2x+40)

    = > 18x \: = 10x \: + 200=>18x=10x+200

    = > 8x \: = 200=>8x=200

    = > X \: = 25=>X=25

    \begin{gathered}= > X + 2 \: = 25 \: + 2 \\ \: \: \: \: \: \: \: \: \:\: \: \: = 27\end{gathered}

    =>X+2=25+2

    =27

    So, two consecutive odd integers are 25 and 27 .

    ________________________________

    Reply
  2. [tex] \large{ \bold{ \color{blue}{ \underline{Question : – }}}}[/tex]

    Find two consecutive odd integers such that two – fifth of the smaller exceeds two – ninth of the greater by 4.

    [tex] \large{ \bold{ \color{blue}{ \underline{ \color{blue}{Solution : – }}}}}[/tex]

    Let the smaller odd integer be x and greater odd integer be ( X + 2 )

    [tex] \frac{2}{5} \\ [/tex] of smaller exceedo [tex] \frac{2}{5th} \\ [/tex] of greater odd by 4.

    [tex] => \frac{2x}{5} = \frac{2}{5}(x + 2) + 4 \\ [/tex]

    [tex] => \frac{2x}{5} = \frac{2x + 4 + 36}{9} \\ [/tex]

    [tex] = > 18x \: = 5(2x + 40)[/tex]

    [tex] = > 18x \: = 10x \: + 200[/tex]

    [tex] => 8x \: = 200[/tex]

    [tex] => X \: = 25 [/tex]

    [tex]=> X + 2 \: = 25 \: + 2 \\ \: \: \: \: \: \: \: \: \:\: \: \: = 27[/tex]

    So, two consecutive odd integers are 25 and 27 .

    ___________________________________

    Hope it’s helps uhh….

    Be Brainly~

    Reply

Leave a Comment