evavulate (a)= sin square 60 + cos square 45 (b) = 1 – tam square 30 / 1 + tam square 30 (c) = sin 60 . tan 60 . / cos 30 . cot 30 (d )= 3 cos square 30 + tan square 60 . ( evavulate the following maths ) trignamotary questions About the author Camila
Answer: L.H.S: (√3 + 1) (3 – cot 30°) = (√3 + 1) (3 – √3) [∵cos 30° = √3] = (√3 + 1) √3 (√3 – 1) [∵(3 – √3) = √3 (√3 – 1)] = ((√3)2– 1) √3 [∵ (√3+1)(√3-1) = ((√3)2 – 1)] = (3-1) √3 = 2√3 Similarly solving R.H.S: tan3 60° – 2 sin 60° Since, tan 60o = √3 and sin 60o = √3/2, We get, (√3)3 – 2.(√3/2) = 3√3 – √3 = 2√3 Therefore, Reply
Answer:
L.H.S: (√3 + 1) (3 – cot 30°) = (√3 + 1) (3 – √3) [∵cos 30° = √3] = (√3 + 1) √3 (√3 – 1) [∵(3 – √3) = √3 (√3 – 1)] = ((√3)2– 1) √3 [∵ (√3+1)(√3-1) = ((√3)2 – 1)] = (3-1) √3 = 2√3 Similarly solving R.H.S: tan3 60° – 2 sin 60° Since, tan 60o = √3 and sin 60o = √3/2, We get, (√3)3 – 2.(√3/2) = 3√3 – √3 = 2√3 Therefore,