evaluate : (2a + 3b + 4c) power 2 + (2a – 3b + 4c) power 2 + (2a + 3b – 4c) power 2​

2 thoughts on “evaluate : (2a + 3b + 4c) power 2 + (2a – 3b + 4c) power 2 + (2a + 3b – 4c) power 2​”

1. AnswerWe know,

   (x+y+z)2=x2+y2+z2+2xy+2yz+2zx [Identity]

   Here,

   x=2a

   y=3b

   z=4c

   Putting Values in Identity, We get :

   ⇒ (2a+3b+4c)2=(2a)2+(3b)2+(4c)2+2(2a)(3b)+2(3b)(4c)+2(4c)(2a)

   =4a2+9b2+16c2+12ab+24bc+16ca

   Step-by-step explanation:

   hσpє ítѕ hєlpful tσ чσu

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2. Answer:

   (x+y+z)

   2

   =x

   2

   +y

   2

   +z

   2

   +2xy+2yz+2zx [Identity]

   Here,

   x=2a

   y=3b

   z=4c

   Putting Values in Identity, We get :

   ⇒ (2a+3b+4c)

   2

   =(2a)

   2

   +(3b)

   2

   +(4c)

   2

   +2(2a)(3b)+2(3b)(4c)+2(4c)(2a)

   =4a

   2

   +9b

   2

   +16c

   2

   +12ab+24bc+16ca

   Reply