evaluate: (1) 103^3 – 93^3 (2) 2x^2+13x+20 (by splitting the middle term) please answer the question I mark you brainiest please help itzheartgirl About the author Bella
Step-by-step explanation: 1) 103^3-93^3 using a^3-b^3=(a-b) (a^2+b^2+ab) =(103-93) (103^2+93^2+103×93) =(10) (10609+8649+9579) =(10) (28837) =288370 2) 2x^2+13x+20 2x^2+8x+5x+20 =2x(x+4)+5(x+4) =(2x+5)(x+4) Reply
Step-by-step explanation:
1) 103^3-93^3
using a^3-b^3=(a-b) (a^2+b^2+ab)
=(103-93) (103^2+93^2+103×93)
=(10) (10609+8649+9579)
=(10) (28837)
=288370
2) 2x^2+13x+20
2x^2+8x+5x+20
=2x(x+4)+5(x+4)
=(2x+5)(x+4)