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EF||QR find FR PE=2.5 cm PF=2cm
EQ=4cm FR= ?​

By Arianna

EF||QR find FR PE=2.5 cm PF=2cm
EQ=4cm FR= ?​

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Arianna

3

2 + 2

2 + 2[3

2 +2

2

-{

2+

2

– 2(3

which of the following mesurements of sides can form a triangle
a) 8cm, 9cm ,11cm
b) 5cm , 2cm, 3cm
c)3cm , 4cm ,7

1 thought on “EF||QR find FR PE=2.5 cm PF=2cm<br />EQ=4cm FR= ?​”

  1. Answer:

    The basic proportionality theorem states that if a line is drawn parallel to one side of a triangle and it intersects the other two sides at two distinct points then it divides the two sides in the same ratio.

    It is given that PE=3.9 cm, EQ=3 cm, PF=3.6 cm and FR=2.4 cm.

    Using the basic proportionality theorem, we have

    EQ

    PE

    =

    3

    3.9

    =1.3

    FR

    PF

    =

    2.4

    3.6

    =1.5

    Since

    EQ

    PE

    =

    FR

    PF

    Hence, EF is not parallel to QR.

    Reply

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