[tex]\huge \sf \bf {\boxed{\underline {\red{\underline {✠Aɴʂᴡᴇʀ࿐ :−}}}}} [/tex] Firstly 190$ is even so the number of 5$ is even and the number of 2$ is a multiple of 5. So 5k lots of 2$ 2n lots of 5$ But if there are 4 less 5$ notes than 2$ notes 5k – 4 = 2n Where 5k + 2n = 190$ Or k * 10$ + n * 10$ = 190$ Then k+n = 19 Write n = 19 – k 5k – 4 = 38 – 2k 7k = 42 k = 6 n = 13 So we have 130$ Of 5$ notes and 60$ of 2$ notew that’s 26 5$ notes and 30 2$ notes. Reply
Firstly 190is even so the number of 5isevensothenumberof5 is even and the number of 2$ is a multiple of 5. So 5k lots of 2$ 2n lots of 5$ But if there are 4 less 5notes than 2notesthan2 notes 5k – 4 = 2n Where 5k + 2n = 190$ Or k * 10+ n * 10+n∗10 = 190$ Then k+n = 19 Write n = 19 – k 5k – 4 = 38 – 2k 7k = 42 k = 6 n = 13 So we have 130Of 5Of5 notes and 60of 2of2 notew that’s 26 5notes and 30 2notesand302 notes. Reply
[tex]\huge \sf \bf {\boxed{\underline {\red{\underline {✠Aɴʂᴡᴇʀ࿐ :−}}}}} [/tex]
Firstly 190$ is even so the number of 5$ is even and the number of 2$ is a multiple of 5.
So 5k lots of 2$
2n lots of 5$
But if there are 4 less 5$ notes than 2$ notes
5k – 4 = 2n
Where 5k + 2n = 190$
Or k * 10$ + n * 10$ = 190$
Then k+n = 19
Write n = 19 – k
5k – 4 = 38 – 2k
7k = 42
k = 6
n = 13
So we have 130$ Of 5$ notes and 60$ of 2$ notew
that’s 26 5$ notes and 30 2$ notes.
Firstly 190is even so the number of 5isevensothenumberof5 is even and the number of 2$ is a multiple of 5.
So 5k lots of 2$
2n lots of 5$
But if there are 4 less 5notes than 2notesthan2 notes
5k – 4 = 2n
Where 5k + 2n = 190$
Or k * 10+ n * 10+n∗10 = 190$
Then k+n = 19
Write n = 19 – k
5k – 4 = 38 – 2k
7k = 42
k = 6
n = 13
So we have 130Of 5Of5 notes and 60of 2of2 notew
that’s 26 5notes and 30 2notesand302 notes.