dy/DX=1/x+y with y(0)=1 and step size h=0.1 then value of k1 as defined in Runge kutta method
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1 thought on “dy/DX=1/x+y with y(0)=1 and step size h=0.1 then value of k1 as defined in Runge kutta method<br />​”

1. Given:

   dy/dx = 1/x+y

   y(0) = 1

   h = 0.0

   To find:

   The value of k₁ as defined in the Runge Kutta method

   Solution:

   We have f(x,y) = 1/x+y

   x₀ = 0

   y₀ = 1

   h = 0.1

   k₁ = hf(x₀,y₀)

   k₁ = 0.1f(0,1)

   k₁ = 0.1 × (1/0+1)

   k₁ = 0.1

   Therefore, the value of k₁ is 0.1

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