During an experiment, a signalfrom a spaceship reached theground station in five minutes.What was the distance of thespaceship from the groundstation? The signal travels at thespeed of light, that is, 3 × 108m s–1. About the author Gianna
Answer: 9 x 10^10 m (^ = rise to) Step-by-step explanation: Speed = 3 x 10^8 m/s Time taken = 5 minutes = 300 seconds Speed = Distance/Time taken Distance = Speed x Time taken Distance = 3 x 10^8 x 300 Distance = 900 x 10^8 Distance = 9 x 10^10 Therefore, Distance is equal to 9 x 10^10 m. Reply
Answer: Step-by-step explanation: Time taken=5min=5×60s=300sec speed of signal u =3×10^8 m/s Distance=?? we know that speed= Distance/time Distance= Speed×Time putting the value Distance= 3×10^8 × 300 Distance = 9×10^10m Reply
Answer:
9 x 10^10 m (^ = rise to)
Step-by-step explanation:
Speed = 3 x 10^8 m/s
Time taken = 5 minutes = 300 seconds
Speed = Distance/Time taken
Distance = Speed x Time taken
Distance = 3 x 10^8 x 300
Distance = 900 x 10^8
Distance = 9 x 10^10
Therefore, Distance is equal to 9 x 10^10 m.
Answer:
Step-by-step explanation:
Time taken=5min=5×60s=300sec
speed of signal u =3×10^8 m/s
Distance=??
we know that
speed= Distance/time
Distance= Speed×Time
putting the value
Distance= 3×10^8 × 300
Distance = 9×10^10m