Discuss the nature of the roots of the following equations : ☆ 4x² – 5x – 3 = 0 About the author Cora
Equation :– 4x² – 5x – 3 = 0 ☆ Comparing with ax²+bx+c=0 We get a=4 b=-5 c=-3 Discriminant =b²-4ac => (-5)² -4(4)(-3) => 25 +48 => 73 > 0 Therefore The equation has two distinct roots . Reply
The given equation is 4x² – 5x – 3 = 0. ━━━━━━━━━━━━━━━━━ Comparing with ax² + bx + c = 0 We get, ➣ a = 4 ➣ b = -5 ➣ c = -3 ∴ Discriminant = b² – 4ac ➺ (-5)² – 4.4.(-3) ➺ 25 + 48 ➺ 73 > 0 ❑ Therefore, Hence, the given equation has two distinct real roots. ━━━━━━━━━━━━━━━━━ Reply
Equation :– 4x² – 5x – 3 = 0
☆ Comparing with ax²+bx+c=0
We get
a=4
b=-5
c=-3
Discriminant =b²-4ac
=> (-5)² -4(4)(-3)
=> 25 +48
=> 73 > 0
Therefore
The given equation is 4x² – 5x – 3 = 0.
━━━━━━━━━━━━━━━━━
We get,
➣ a = 4
➣ b = -5
➣ c = -3
∴ Discriminant = b² – 4ac
➺ (-5)² – 4.4.(-3)
➺ 25 + 48
➺ 73 > 0
❑ Therefore,
━━━━━━━━━━━━━━━━━