Answer: [tex]2 {x}^{2} – x – 2 = 0[/tex] [tex]a = 2 \: \: \: b = – 1 \: \: \: c = – 2[/tex] [tex] {b}^{2} – 4ac = { – 1}^{2} – 4 \times 2 \times – 2 = 15[/tex] [tex]x = \frac{ – b + \sqrt{15} }{2a} = \frac{1 + \sqrt{15} }{4} [/tex] [tex]x = \frac{1 – \sqrt{15} }{4} [/tex] that’s is your answer Reply
Answer:
[tex]2 {x}^{2} – x – 2 = 0[/tex]
[tex]a = 2 \: \: \: b = – 1 \: \: \: c = – 2[/tex]
[tex] {b}^{2} – 4ac = { – 1}^{2} – 4 \times 2 \times – 2 = 15[/tex]
[tex]x = \frac{ – b + \sqrt{15} }{2a} = \frac{1 + \sqrt{15} }{4} [/tex]
[tex]x = \frac{1 – \sqrt{15} }{4} [/tex]
that’s is your answer
Answer:
day to answer
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