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CONSTRUCT TRIANGLE ABC SUCH THAT AB = 9.8CM, BC = 6.5CM AND ABC = 88 DEGREE
B = ^
CONSTRUCT THE PERPANDECULAR BISECTO

By Piper

CONSTRUCT TRIANGLE ABC SUCH THAT AB = 9.8CM, BC = 6.5CM AND ABC = 88 DEGREE
B = ^
CONSTRUCT THE PERPANDECULAR BISECTOR OF AB SUCH THAT IT CUTS AC. MEASURE THE LENGTH BS, SUCH THAT S IS THE POINT WHERE THE PERPENDICULAR BISECTOR AB CUTS AC

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Piper

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2 thoughts on “CONSTRUCT TRIANGLE ABC SUCH THAT AB = 9.8CM, BC = 6.5CM AND ABC = 88 DEGREE<br /> B = ^ <br /> CONSTRUCT THE PERPANDECULAR BISECTO”

  1. Given : TRIANGLE ABC SUCH THAT AB = 9.8CM, BC = 6.5CM AND ABC = 88 DEGREE

    To Find : Construct triangle ABC

    Construct perpendicular bisector of AB , cut AC at S. Measure BS

    Solution:

    Step 1 : Draw a line segment BA = 9.8cm

    Step 2 : draw an angle of 88° at B on BA using protractor

    Step 3 : Using compass width = 6.5 cm and B as center , mark a point C on angle drawn in previous step

    Step 4 : Join BC

    Step 5 : Draw perpendicular bisector of AB cutting AC at S

    Step 6 : Join BS

    Step 7 : Measure BS = 5.9 cm

    Perpendicular Bisector of AB

    Step 1 : Use suitable compass width and taking A as center draw arcs on both sides

    Step 2 : Keeping compass width same and taking A as center draw arcs on both sides such that it intersects arc drawn in previous steps at X and Y

    Step 3: Join XY intersecting AB at M

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