consider the arithmetic sequence is 7,12,17 a) what is the common difference b) what is difference between the sum of first 20 term and the sum of next 20 term ? About the author Remi
a) D= a_2-a_1 =12-7= 5 Common difference= 5 b) [tex] \tt \: = \frac{ 20 }{ 2 } (2(7)+(40-1)(5)) \\ \tt \: 10\left(2\times 7+\left(40-1\right)\times 5\right) \\ \tt \: 10\left(14+\left(40-1\right)\times 5\right)\\ \tt \:10\left(14+39\times 5\right)\\ \tt \: 10\left(14+195\right)\\ \tt \: 10\times 209 \\ \tt \:2090 ——–i) \\ \\ \tt \:= \frac{ 20 }{ 2 } (2(7)+(20-1)(5))\\ \tt \:10\left(2\times 7+\left(20-1\right)\times 5\right)\\ \tt \: 10\left(14+\left(20-1\right)\times 5\right) \\ \tt \:10\left(14+\left(20-1\right)\times 5\right)\\ \tt \: 10\left(14+19\times 5\right)\\ \tt \: 10\left(14+95\right)\\ \tt \: 10\times 109 \\ \tt \:1090——-ii)[/tex] From Eq i) and ii) 2090-1090=1000 Difference between the sum of first 20 term and the sum of next 20 term= 1000 [tex] \sf \: @WildCat7083[/tex] Reply
a) D= a_2-a_1
=12-7= 5
Common difference= 5
b)
[tex] \tt \: = \frac{ 20 }{ 2 } (2(7)+(40-1)(5)) \\ \tt \: 10\left(2\times 7+\left(40-1\right)\times 5\right) \\ \tt \: 10\left(14+\left(40-1\right)\times 5\right)\\ \tt \:10\left(14+39\times 5\right)\\ \tt \: 10\left(14+195\right)\\ \tt \: 10\times 209 \\ \tt \:2090 ——–i) \\ \\ \tt \:= \frac{ 20 }{ 2 } (2(7)+(20-1)(5))\\ \tt \:10\left(2\times 7+\left(20-1\right)\times 5\right)\\ \tt \: 10\left(14+\left(20-1\right)\times 5\right) \\ \tt \:10\left(14+\left(20-1\right)\times 5\right)\\ \tt \: 10\left(14+19\times 5\right)\\ \tt \: 10\left(14+95\right)\\ \tt \: 10\times 109 \\ \tt \:1090——-ii)[/tex]
From Eq i) and ii)
2090-1090=1000
Difference between the sum of first 20 term and the sum of next 20 term= 1000
[tex] \sf \: @WildCat7083[/tex]