Complete the equation of the line through (-6,5) and (-3,–3). Use exact numbers. About the author Bella
Answer: [tex] \frac{y – 5}{x – ( – 6)} = \frac{5 – ( – 3)}{ – 6 – ( – 3)} \\ \frac{y – 5}{x + 6} = \frac{8}{ – 3} \\ – 3 \times (y – 5) = 8 \times (x + 6) \\ – 3y + 15 = 8x + 48 \\ 8x + 3y + 48 – 15 = 0 \\ 8x + 3y + 33 = 0[/tex] Reply
Answer: y-y1=y2-y1/X2-X1(X-X1) y-5=-3-5/-3-(-6)(X-(-6) y-5=-2/3(X+6) y-5=2X+12/3 y=2X+9+5 y=2X+14 Reply
Answer:
[tex] \frac{y – 5}{x – ( – 6)} = \frac{5 – ( – 3)}{ – 6 – ( – 3)} \\ \frac{y – 5}{x + 6} = \frac{8}{ – 3} \\ – 3 \times (y – 5) = 8 \times (x + 6) \\ – 3y + 15 = 8x + 48 \\ 8x + 3y + 48 – 15 = 0 \\ 8x + 3y + 33 = 0[/tex]
Answer:
y-y1=y2-y1/X2-X1(X-X1)
y-5=-3-5/-3-(-6)(X-(-6)
y-5=-2/3(X+6)
y-5=2X+12/3
y=2X+9+5
y=2X+14