cm. What17) The base of an isosceles triangle is 4/3 cm. The perimeter of the triangle is 4is the length of either of the remaining equal sides?1ite About the author Kylie
Step-by-step explanation: Let the length of equal sides be x cm . Perimeter = x cm + x cm + Base = 4 2/15 cm 2x + 4/3 = 62/15 On transposing 4/3 to R.H.S, we obtain 2x = 62/15 – 4/3 2x = 62 – 4 x 5/15 = 62 – 20/15 2x = 42/15 On dividing both sides by 2, we obtain 2x/2 = 42/15 x1/2 x = 7/5 = 1 2/5 Therefore, the length of equal sides is 1 2/5 c m. Reply
Step-by-step explanation:
Let the length of equal sides be x cm
. Perimeter = x cm + x cm + Base
= 4 2/15 cm 2x + 4/3 = 62/15
On transposing 4/3 to R.H.S,
we obtain 2x = 62/15 – 4/3 2x = 62 – 4 x 5/15 = 62 – 20/15 2x = 42/15
On dividing both sides by 2, we obtain
2x/2 = 42/15 x1/2 x = 7/5 = 1 2/5
Therefore, the length of equal sides is 1 2/5 c m.