Check whether 3 , 4 & 7 can be the sides of a triangle by using triangular inequality. About the author Arianna
Answer: [tex] as \:larger \: side \: is \: 7 \: \\ so \: c = 7 \: \: \: a = 3\: \: \: b = 4 \: \: \: \\ {c}^{2} = {a}^{2} + {b}^{2} \\ ( {7)}^{2} = ( {3)}^{2} + {(4)}^{2} \\ 49 = 9 + 16 \\ 49 ≠ 25 \\ so \: given \: sides \: doesnot \: form \: right \: triangle[/tex] Reply
Answer:
[tex] as \:larger \: side \: is \: 7 \: \\ so \: c = 7 \: \: \: a = 3\: \: \: b = 4 \: \: \: \\ {c}^{2} = {a}^{2} + {b}^{2} \\ ( {7)}^{2} = ( {3)}^{2} + {(4)}^{2} \\ 49 = 9 + 16 \\ 49 ≠ 25 \\ so \: given \: sides \: doesnot \: form \: right \: triangle[/tex]