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Can someone check this answer for me?
Two ice hockey players are moving towards each other.
Player 1 has a mass of 78k

By Quinn

Can someone check this answer for me?
Two ice hockey players are moving towards each other.
Player 1 has a mass of 78kg and a velocity of 7.5 m/s
Player 2 has a mass of 91kg and a velocity of -5.5m/s
During the collision, total momentum of the players is conserved.
Immediately after the collision, the players move together towards the right
Calculate the velocity of the players after the collision.

My working out is
Momentum of player 1 = 78×7.5=585
Momentum of player 2= 91x-5.5=-500.5
Total momentum before event= 585+-500.5 = 84.5
momentum before (84.5) = momentum after (also 84.5)
84.5 = velocity x the two players total mass
84.5 = velocity x (78+91)
84.5 / 169 = 0.5m/s
So their velocity is 0.5m/s as they move to the right.
Can someone tell me if this is correct?

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Quinn

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static int i;
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};
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int main() {
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1 thought on “Can someone check this answer for me?<br /> Two ice hockey players are moving towards each other.<br /> Player 1 has a mass of 78k”

  1. its correct

    My working out is

    Momentum of player 1 = 78×7.5=585

    Momentum of player 2= 91x-5.5=-500.5

    Total momentum before event= 585+-500.5 = 84.5

    momentum before (84.5) = momentum after (also 84.5)

    84.5 = velocity x the two players total mass

    84.5 = velocity x (78+91)

    84.5 / 169 = 0.5m/s

    it moves to the right

    Reply

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