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can anyone help with this : it’ll help a lot 9(3b+8)=12(b+14)​

By Autumn

can anyone help with this : it’ll help a lot 9(3b+8)=12(b+14)​

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Autumn

if in an AP the sum of first m terms is n and thr sum of its first n terms is m, then prove that the sum of its first (m+n) terms

When numerator of a fraction is increased by 40% and denominator increased by 80% the resultant fraction becomes
14/27
F

1 thought on “can anyone help with this : it’ll help a lot 9(3b+8)=12(b+14)​”

  1. Step-by-step explanation:

    [tex]\text{9(3b+8)=12(b+14)}[/tex]

    [tex]

    \text{27b + 72 = 12b + 168}

    [/tex]

    [tex]\text{27b – 12b = 168 – 72}

    [/tex]

    [tex]\text{15b = 96}[/tex]

    [tex]\text{b} = \frac{96}{15}[/tex]

    [tex]\text{b} = \frac{32}{5}[/tex]

    [tex]\text{b} = {6}\frac{2}{5}[/tex]

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