[tex] \sf \: \large \: \: Area \: of \: rhombus \: = \frac{1}{2} \times d {}^{1} \times d {}^{2} [/tex] We have given that In a rhombus diagonal ¹ ( d¹ ) = 13 cm diagonal ² ( d ² ) = 16 cm So , [tex] \sf \: Area \: of \: rhombus = \frac{1}{2} \: \times 13 \times 16 \\ \\ \sf \: \: \: \: \: \: \: \: \: \: = 13 \: cm \times 8 cm\\ \\ \sf \: = 108 \: cm \: {}^{2} [/tex] Hence the area of rhombus is 108 cm ² Reply
The area of rhombus = 1/2×d1×d2 Where diagonal d1 = 12 cm and d2 = 16 cm The area of rhombus = 1/2×12×16 The area of rhombus = 96 cm² Therefore, the area of rhombus = 96 cm² Reply
[tex] \sf \: \large \: \: Area \: of \: rhombus \: = \frac{1}{2} \times d {}^{1} \times d {}^{2} [/tex]
We have given that
In a rhombus
diagonal ¹ ( d¹ ) = 13 cm
diagonal ² ( d ² ) = 16 cm
So ,
[tex] \sf \: Area \: of \: rhombus = \frac{1}{2} \: \times 13 \times 16 \\ \\ \sf \: \: \: \: \: \: \: \: \: \: = 13 \: cm \times 8 cm\\ \\ \sf \: = 108 \: cm \: {}^{2} [/tex]
Hence the area of rhombus is 108 cm ²
The area of rhombus = 1/2×d1×d2
Where diagonal d1 = 12 cm and d2 = 16 cm
The area of rhombus = 1/2×12×16
The area of rhombus = 96 cm²
Therefore, the area of rhombus = 96 cm²