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Box I contains 3 red (R1, R2, R 3) and 2 blue (B
B, 2) marbles while box II contains 2 red (R2), R_2)
and 4 blue (B1, B2

By Athena

Box I contains 3 red (R1, R2, R 3) and 2 blue (B
B, 2) marbles while box II contains 2 red (R2), R_2)
and 4 blue (B1, B2, B3, B2) marbles. A fair coin
is tossed. If the coin turns up head, a marble is
chosen from box I, if it turns up tail, a marble is
chosen from box II.
Describe the sample space.​

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Athena

Solve2x + 1/2 +(3 – x) >7, x € R. Also graph the solution set on the number line.
2​

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1 thought on “Box I contains 3 red (R1, R2, R 3) and 2 blue (B<br />B, 2) marbles while box II contains 2 red (R2), R_2)<br />and 4 blue (B1, B2”

  1. Step-by-step explanation:

    Correct option is

    B

    52

    A] Event A = { o red marbles is chosen}

    B1= {Box 1 is chosen}

    B2= {Box 2 is chosen}

    By formula for total probability

    P(A)=P(A/B1)P(B1)+P(A1B1)P(B2)

    P(B1)=P(B2)=21,P(A1B1)=53

    P(A1B2)=102=51

    So, P(A)=21×53+21×51=101=5

    hope this helped you

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