(b) Prove that the tangents drawn from an external pointof circle make equal angles with line joining centre and external point . in figure , angle AOB = 100 degree find angle APO About the author Charlie
Step-by-step explanation: A circle with centre O and a point P outside it. PA and PB are @ tangents to circle To prove: ∠AOP=∠BOP and,∠APO=∠BPO Proof: In ΔAOPandΔBOP PA=PB (tangents drawn from an external points are equal) OA=OB (radii of same circle ) ΔAOP≅ΔBOP(SSS) ∴∠AOP=∠BOP and∠APO=∠BPO(CPCT) This is the right answer for your question. Reply
Step-by-step explanation:
A circle with centre O and a point P outside it.
PA and PB are @ tangents to circle
To prove:
∠AOP=∠BOP
and,∠APO=∠BPO
Proof:
In ΔAOPandΔBOP
PA=PB (tangents drawn from an external points are equal)
OA=OB (radii of same circle )
ΔAOP≅ΔBOP(SSS)
∴∠AOP=∠BOP
and∠APO=∠BPO(CPCT)
This is the right answer for your question.