Answer is 110 degreee and you have to show process. Pq is parallel to st . ab is a straight line find angle bst​

1 thought on “Answer is 110 degreee and you have to show process. Pq is parallel to st . ab is a straight line find angle bst​”

1. [tex]Since, PQ∥ST

   ∴∠PQS=∠QST (Alternate angles)

   ⇒∠QST=98∘

   ⇒∠QSA+∠AST=98∘

   ⇒∠AST=98∘−28∘=70∘

   Now, AB is a straight line.

   ∴∠AST+∠TSB=180∘ (linear pair)

   ⇒∠TSB=180∘−70∘=110∘.

   [/tex]

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