an object is projected with velocity of 40 m/s at an angle of 45 tho the horizontal . air resistance is negligible .what is the speed of the object after 5.00s About the author Alaia
By equations of motion, V = U+at V = [40 cos45 (i) + 40 sin45 (j)] + [g (-j) . 5] V = 40/√2(i) + 40/√2(j) – 50(j) V = 28.28(i) + 28.28(j) – 50(j) V = 28.28(i) – 21.72(j) V = √(28.28)²+(21.72)² V = 35.65 m/s Reply
By equations of motion,
V = U+at
V = [40 cos45 (i) + 40 sin45 (j)] + [g (-j) . 5]
V = 40/√2(i) + 40/√2(j) – 50(j)
V = 28.28(i) + 28.28(j) – 50(j)
V = 28.28(i) – 21.72(j)
V = √(28.28)²+(21.72)²
V = 35.65 m/s