An elevator descends into a mine shaft at the rate of 7 m/min. If the descent starts from 10 m above the ground level, how l

2 thoughts on “<br />An elevator descends into a mine shaft at the rate of 7 m/min. If the descent starts from 10 m above the ground level, how l”

1. • The elevator take 50 min to reach -340m.

   Step-by-step explanation:

   Given:–

   • An elevator descends into a mine shaft at the rate of 7 m/min.

   • The descent starts from 10 m above the ground level.

   To Find:–

   • How long will it take to reach –340m.

   Solution:–

   Total Distance = 340m + 10m = 350m

   As given,

   Rate/Speed = 7m/min

   Time = [tex]\dfrac{Distance}{Speed}[/tex]

   Time = [tex]\dfrac{350}{7}[/tex]

   Time = [tex]50\:min[/tex]

   Hence, The elevator take 50 min to reach –340m.

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2. Solution –

   • An elevator descends into a mine shaft at a rate of 7 m/min.

   • The descent starts at a height of 10m above the ground .

   • It has to reach a depth of -340 m .

   We have to find how long it takes the elevator to reach that depth .

   Let us proceed.

   Total distance to be covered –

   > 340m + 10m

   > 350 m .

   The rate is @ 7 m/min

   Time taken –

   > 350/7 min

   > 50 min .

   Answer . It takes 50min for the elevator to descent into the required height in the mine shaft .

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