An electron moving with a velocity of 5×10³m/s enters into an electric field and acquires uniform acceleration of 10³m/s² in the direction of initial velocity. Find:
(i) Find out the time in which the electron’s velocity will be doubled
(ii) How much distance the electron would cover in this time
Answer:
Answer i: 5
Explanation: Initial velocity of the electron is u =5×10
4
m/s
Acceleration of the electron is a=10
4
m/s
2
From first equation of motion,
v=u+at
2u=u+at
t=u/a=(5×10
4
)/(10
4
)=5s
(C) 5
Answer ii: An electron moving with a velocity of 5 × 10^4 m s^-1 enters into a uniform electric field and acquires. An electron moving with a velocity of 5 × 104 m s-1 enters into a uniform electric field and acquires a uniform acceleration of 104 m s–2 in the direction of its initial motion.
Explanation:
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Answer:
An electron moving with a velocity of 5×104 ms−1 enters into a uniform electric field and acquires a uniform acceleration of 104 ms−2 in the direction of its initial motion. Calculate the time(in s) in which the electron would acquire a velocity double of its initial velocity.
Explanation:
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