An ant climbs up five stairs, each of width 20 and height 20 . Find the distance covered and displacement
of ant, if it starts from the bottom, and reaches the start of the sixth staircase
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of ant, if it st”
Distance- is a scalar quantity that refers to “how much ground an object has covered” during its motion. Displacement – is a vector quantity that refers to “how far out of place an object is”; it is the object’s overall change in position.
Distance- is a scalar quantity that refers to “how much ground an object has covered” during its motion. Displacement – is a vector quantity that refers to “how far out of place an object is”; it is the object’s overall change in position.
GIVEN :-
An Ant climbs up five stairs each of the width 20 cm and height 20 cm.
Width of each stair = 20 cm
Height of each stair = 20 cm
TO FIND :-
Total distance covered and displacement of the ant.
SOLUTION :-
The ant covers a distance of 20 + 20 = 40 cm for each stair. (20 cm for moving on the stair, and 20 cm for climbing the stair).
Number of stairs = 5
Total distance covered = 5 × 40
⇒Total distance covered = 200 cm
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Using Pythagoras theorem, we can find the displacement for each stair :-
H² = P² + B²
⇒ H² = (20)² + (20)²
⇒ H² = 400 + 400
⇒ H = √800
⇒ H = 20√2 cm
Total number of stairs = 5
Total displacement = 5 × 20√2
⇒Total displacement = 100√2 cm
Hence, the ant covers a distance of 200 cm and has an overall displacement of 100√2cm.
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