ABCD is trapezium as shown in figure. Distance between two parallel sides AB
and CD is h. DC = 2AB = 2h. Area of ABCD = 384.

ABCD is trapezium as shown in figure. Distance between two parallel sides AB
and CD is h. DC = 2AB = 2h. Area of ABCD = 384. Find h.

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1 thought on “ABCD is trapezium as shown in figure. Distance between two parallel sides AB<br /> and CD is h. DC = 2AB = 2h. Area of ABCD = 384.”

  1. Answer:

    384 = (1/2) * (h+h) * 2h

    384=(1/2) * 2h * 2h

    or, 384*2=[tex]4h^{2}[/tex]

    or, 192=[tex]h^{2}[/tex]

    or, h=[tex]8\sqrt{3}[/tex]

    Step-by-step explanation:

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