A volume of gas starts at a pressure of 10 atmospheres (atm) and a temperature of 27°C. If the temperature is increased by

A volume of gas starts at a pressure of 10 atmospheres (atm) and a temperature of 27°C. If the temperature is increased by 75°C and the volume of the gas remains constant, what is the new pressure?

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  1. Given that,

    Initial pressure = 10 atm

    Initial temperature = 27 °C

    Final temperature = 75 °C

    We have to find final pressure of the gas[tex].[/tex]

    ❖ As per Gay Lussac’s law at constant volume, pressure of an ideal gas is directly proportional to the temperature.

    Mathematically, P ∝ T

    First of all we have to convert the temperature into kelvin.

    ⟩ Initial temperature = 27 °C = 300 K

    ⟩ Final temperature = 75 °C = 348 K

    By substituting the given values;

    [tex]\sf:\implies\:\dfrac{P_1}{P_2}=\dfrac{T_1}{T_2}[/tex]

    [tex]\sf:\implies\:\dfrac{10}{P_2}=\dfrac{300}{348}[/tex]

    [tex]\sf:\implies\:P_2=\dfrac{10\times 348}{300}[/tex]

    [tex]\sf:\implies\:P_2=\dfrac{348}{30}[/tex]

    [tex]:\implies\:\underline{\boxed{\bf{\gray{P_2=11.6\:atm}}}}[/tex]

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