A varies directly as the sum of two quantitiesB and ‘C’. ‘B’ in turn varies directly as ‘X’ and ‘cvaries inversely as ‘x. When x = 1 or 2. A = 3. Findthe value of A when x = 4. About the author Adeline
Answer: Step-by-step explanation: A varies directly as sum of B and C => A= k(B+C) (k is some constant) now, B varies directly as x => B=m1*x (m1 is some constant) and C varies inversely as x => C=m2/x (m2 is some constant) =>A=k(m1*x + m2/x) =>A=px + q/x (p=k*m1 and q=k*m2 are replaced constants) so, for x=2, 6= 2p + q/2 and for x=4, 9=4p + q/4 solving for p and q, p=2 q=4 =>A=2x + 4/x So, for x=16, A=32.25 Reply
Answer:
Step-by-step explanation:
A varies directly as sum of B and C
=> A= k(B+C) (k is some constant)
now, B varies directly as x
=> B=m1*x (m1 is some constant)
and C varies inversely as x
=> C=m2/x (m2 is some constant)
=>A=k(m1*x + m2/x)
=>A=px + q/x (p=k*m1 and q=k*m2 are replaced constants)
so, for x=2,
6= 2p + q/2
and for x=4,
9=4p + q/4
solving for p and q,
p=2
q=4
=>A=2x + 4/x
So, for x=16,
A=32.25