A tyre exerts a force of 50 Newton calculate the pressure exerted by the tyre on the road if area of contract is 600 square CM About the author Gianna
Answer :- Pressure exerted by the tyre on the road is 833.33 Pascal . Explanation :- We have :- → Magnitude of force = 50 N → Area of contact = 600 cm² ________________________________ Firstly, let’s convert the unit of contact area from cm² to m² . ⇒ 1 cm² = 0.0001 m² ⇒ 600 cm² = 600(0.0001) ⇒ 0.06 m² Now, we know that :- Pressure = Force/Contact Area Substituting values, we get :- ⇒ Pressure = 50/0.06 ⇒ Pressure = 50/(6/100) ⇒ Pressure = 5000/6 ⇒ Pressure = 833.33 Pa Reply
Answer: Question :- A tyre exerts a force of 50 Newton calculate the pressure exerted by the tyre on the road if area of contract is 600 square cm. Given :- A tyre exerts a force of 50 Newton area of contract is 600 square cm Find Out :- Calculate the pressure exerted by the tyre on the road Solution :- Given in the question : [tex]\curlyeqsucc[/tex] Magnitude of force = 50 N [tex]\curlyeqsucc[/tex] Area of contact = 600 cm² Firstly, let’s convert the unit of contact area from cm² to m² . [tex]\curlyeqsucc[/tex] 600 cm² = 600 × 0.0001 m² [tex]\curlyeqsucc[/tex] 0.06 m² Now, we know that :- [tex]\red{ \boxed{\sf{Pressure = \dfrac{Force}{Area}}}}[/tex] Substituting values, we get :- [tex]\implies[/tex] Pressure = [tex]\tt{\dfrac{50}{0.06}}[/tex] [tex]\implies[/tex] Pressure = [tex]\tt{\dfrac{50}{(6/100)}}[/tex] [tex]\implies[/tex] Pressure = [tex]\tt\cancel{{\dfrac{5000}{6}}}[/tex] [tex]\implies[/tex] Pressure = 833.33 Pa Therefore, the pressure exerted by the tyre on the road is 833.33 Pascal. Reply
Answer :-
Pressure exerted by the tyre on the road is 833.33 Pascal .
Explanation :-
We have :-
→ Magnitude of force = 50 N
→ Area of contact = 600 cm²
________________________________
Firstly, let’s convert the unit of contact area from cm² to m² .
⇒ 1 cm² = 0.0001 m²
⇒ 600 cm² = 600(0.0001)
⇒ 0.06 m²
Now, we know that :-
Pressure = Force/Contact Area
Substituting values, we get :-
⇒ Pressure = 50/0.06
⇒ Pressure = 50/(6/100)
⇒ Pressure = 5000/6
⇒ Pressure = 833.33 Pa
Answer:
Question :-
Given :-
Find Out :-
Solution :-
Given in the question :
[tex]\curlyeqsucc[/tex] Magnitude of force = 50 N
[tex]\curlyeqsucc[/tex] Area of contact = 600 cm²
Firstly, let’s convert the unit of contact area from cm² to m² .
[tex]\curlyeqsucc[/tex] 600 cm² = 600 × 0.0001 m²
[tex]\curlyeqsucc[/tex] 0.06 m²
Now, we know that :-
[tex]\red{ \boxed{\sf{Pressure = \dfrac{Force}{Area}}}}[/tex]
Substituting values, we get :-
[tex]\implies[/tex] Pressure = [tex]\tt{\dfrac{50}{0.06}}[/tex]
[tex]\implies[/tex] Pressure = [tex]\tt{\dfrac{50}{(6/100)}}[/tex]
[tex]\implies[/tex] Pressure = [tex]\tt\cancel{{\dfrac{5000}{6}}}[/tex]
[tex]\implies[/tex] Pressure = 833.33 Pa
Therefore, the pressure exerted by the tyre on the road is 833.33 Pascal.