A train comes to stop in 90 m at an acceleration of 3 m/s2 . Find the speed at which it was travelling

A train comes to stop in 90 m at an acceleration of 3 m/s2 . Find the speed at which it was travelling

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  1. Answer:

    Given that,

    Acceleration a=−0.5m/s2

    Speed v=90km/h=25m/s

    Using equation of motion,

    v=u+at

    Where,

    v = final velocity

    u = initial velocity

    a = acceleration

    t = time

    Put the value into the equation

    Finally train will be rest so, final velocity,v=0

    0=25−0.5t

    25=0.5t

    t=0.525

    t=50 sec

    Again, using equation of motion,

    S=ut+21at2

    Where, s = distance

    v = final velocity

    u = initial velocity

    a = acceleration

    t = time

    Put the value into the equation

    Where S is distance travelled before stop

    s=25×50−21×0.5×(50)2

    s=625 m

    So, the train will go before it is brought to rest is 625 m.

    Hence, A is correct.

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