a total of 6*10^46 electrons follow through a current carrying conductor when connected through external power supply for 20s find the value of current in the conductor About the author Madeline
Answer :- Value of current in the conductor is 4.8 × 10²⁶ A . Explanation :- We have :- → Number of electrons = 6 × 10⁴⁶ → Time taken = 20 s → Charge of an electron = 1.6 × 10⁻¹⁹ C ________________________________ Firstly, let’s calculate the total charge carried by 6 × 10⁴⁶ electrons :- ⇒ Q = 6 × 10⁴⁶ × 1.6 × 10⁻¹⁹ ⇒ Q = 9.6 × 10⁴⁶⁻¹⁹ ⇒ Q = 9.6 × 10²⁷ C ________________________________ Now, we know that :- I = Q/t Substituting values, we get :- ⇒ I = 9.6 × 10²⁷/20 ⇒ I = 0.48 × 10²⁷ ⇒ I = 4.8 × 10²⁶ A Reply
Answer: Given :– A total of 6 × 10⁴⁶;electrons follow through a current carrying conductor when connected through external power supply for 20s To Find :– Current Solution :– We know that Charge = Charge of one electron × Number of electrons Charge = 1.6 × 10-¹⁹ × 6 × 10⁴⁶ Charge = (1.6 × 6) × (10⁴⁶ – ¹⁹) Charge = 9.26 × 10²⁷ Now Current = Charge/Time Current = 9.26 × 10²⁷/20 Current = 0.48 × 10²⁷ A [tex] \\ [/tex] Reply
Answer :-
Value of current in the conductor is 4.8 × 10²⁶ A .
Explanation :-
We have :-
→ Number of electrons = 6 × 10⁴⁶
→ Time taken = 20 s
→ Charge of an electron = 1.6 × 10⁻¹⁹ C
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Firstly, let’s calculate the total charge carried by 6 × 10⁴⁶ electrons :-
⇒ Q = 6 × 10⁴⁶ × 1.6 × 10⁻¹⁹
⇒ Q = 9.6 × 10⁴⁶⁻¹⁹
⇒ Q = 9.6 × 10²⁷ C
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Now, we know that :-
I = Q/t
Substituting values, we get :-
⇒ I = 9.6 × 10²⁷/20
⇒ I = 0.48 × 10²⁷
⇒ I = 4.8 × 10²⁶ A
Answer:
Given :–
A total of 6 × 10⁴⁶;electrons follow through a current carrying conductor when connected through external power supply for 20s
To Find :–
Current
Solution :–
We know that
Charge = Charge of one electron × Number of electrons
Charge = 1.6 × 10-¹⁹ × 6 × 10⁴⁶
Charge = (1.6 × 6) × (10⁴⁶ – ¹⁹)
Charge = 9.26 × 10²⁷
Now
Current = Charge/Time
Current = 9.26 × 10²⁷/20
Current = 0.48 × 10²⁷ A
[tex] \\ [/tex]