A sum of ₹2,800 become ₹2,968 in 2 years at a certain rate of simple interest. Find the sum of money which will become ₹4,840 in 5

2 thoughts on “A sum of ₹2,800 become ₹2,968 in 2 years at a certain rate of simple interest. Find the sum of money which will become ₹4,840 in 5”

1. Step-by-step explanation:

   answer is in the attachment

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2. Given

   • Principal= ₹2,800
   • Time = 2 year’s
   • Amount= ₹2,968

   To Find

   • the Sum Of Money which will become ₹4,840 in 5 years .

   Solution

   [tex] \mathfrak{as \: we \: know \: that}[/tex]

   [tex]\sf Simple\ Interest= Amount – Principal[/tex]

   [tex]{\implies\sf Simple\ Interest= 2968 – 2800}[/tex]

   [tex]{\implies\sf Simple\ Interest= ₹168}[/tex]

   [tex]{\implies \sf \: si = \dfrac{principal \times rate \times time}{100}} [/tex]

   [tex]{\implies \sf \: 168= \dfrac{2800 \times rate \times 2}{100}} [/tex]

   [tex]\implies \sf \: 16800=5600 \times rate[/tex]

   [tex]\implies\sf \: rate = \dfrac{16800}{5600} [/tex]

   [tex]~~~~~~~~~~~~~~~\underline{\boxed{{\tt \: rate = 3\%}}}[/tex]

   Now According to Question

   Let new Principal For 5 year’s on amount 4840 be x

   • SI= Amount- principal
   • Amount= ₹4840
   • Time = 5 year’s
   • Rate= 3%

   [tex] \bold{\mathfrak{as \: we \: know \: that}}[/tex]

   [tex] {\implies\sf \: si = \dfrac{principal \times rate \times time}{100}} [/tex]

   [tex]{\implies\sf \: 4840 – x = \dfrac{x \times 3\times 5}{100} }[/tex]

   [tex]{\implies\sf \: 100(4840 – x) = 15x}[/tex]

   [tex]\implies\sf \: 15x = 484000 – 100x[/tex]

   [tex]\implies\sf \: 115x = 484000 [/tex]

   [tex]\implies\sf \: x = \dfrac{484000}{115} [/tex]

   [tex]~~~~~~~~~~~~~~~\underline{\boxed{\tt \: x =4208 . 6}}[/tex]

   • the sum of money which will become ₹4,840 in 5 years at the same rate of interest is ₹4,208.6.

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