A right triangle whose sides are 15 cm and 20 cm including the right angle is made to relove about its hypotenuse find the volume and surface area of the double cone so formed use π as 3.14 About the author Maya
Step-by-step explanation: Let ABC be the right angled triangle such that AB=15cm and AC=20cm Using Pythagoras theorem we have ⇒BC 2 =AB 2 +AC 2 ⇒BC 2 =15 2 +20 2 ⇒BC 2 =225+400=625 ⇒BC=25cm Let OB=x and OA=y Applying pythagoras theorem in triangles OAB and OAC we have AB 2 =OB 2 +OA 2 ;AC 2 =OA 2 +OC 2 ⇒15 2 =x 2 +y 2 ;20 2 =y 2 +(25−x) 2 ⇒x 2 +y 2 =225;(25−x) 2 +y 2 =400 {(25−x) 2 +y 2 }−{x 2 +y 2 }=400−225 ⇒(25−x) 2 −x 2 =175⇒x=9 Putting x=9 in x 2 +y 2 =225 we get 81+y 2 =225⇒y 2 =144⇒y=12 Thus we have OA=12cm and OB=9cm Volume of the double cone = volume of cone CAA’ + volume of cone BAA’ = 3 1 π×(OA) 2 ×OC+ 3 1 π×(OA) 2 ×OB= 3 1 π×12 2 ×16+ 3 1 π×12 2 ×9 = 3 1 ×3.14×144×253768cm 3 Surface area of the double cone = curved surface area of cone CAA ′ + curved surface area of cone BAA ′ =π×OA×AC+π×OA×AB =(π×12×20+π×12×15)cm =420πcm =420×π=420×3.14 =1318.8cm Reply
Step-by-step explanation:
Let ABC be the right angled triangle such that AB=15cm and AC=20cm
Using Pythagoras theorem we have
⇒BC
2
=AB
2
+AC
2
⇒BC
2
=15
2
+20
2
⇒BC
2
=225+400=625
⇒BC=25cm
Let OB=x and OA=y
Applying pythagoras theorem in triangles OAB and OAC we have
AB
2
=OB
2
+OA
2
;AC
2
=OA
2
+OC
2
⇒15
2
=x
2
+y
2
;20
2
=y
2
+(25−x)
2
⇒x
2
+y
2
=225;(25−x)
2
+y
2
=400
{(25−x)
2
+y
2
}−{x
2
+y
2
}=400−225
⇒(25−x)
2
−x
2
=175⇒x=9
Putting x=9 in x
2
+y
2
=225 we get
81+y
2
=225⇒y
2
=144⇒y=12
Thus we have OA=12cm and OB=9cm
Volume of the double cone = volume of cone CAA’ + volume of cone BAA’
=
3
1
π×(OA)
2
×OC+
3
1
π×(OA)
2
×OB=
3
1
π×12
2
×16+
3
1
π×12
2
×9
=
3
1
×3.14×144×253768cm
3
Surface area of the double cone = curved surface area of cone CAA
′
+ curved surface area of cone BAA
′
=π×OA×AC+π×OA×AB
=(π×12×20+π×12×15)cm
=420πcm
=420×π=420×3.14
=1318.8cm