A regular hexagon is inscribed in a circle. Find theratio of area of circle to the area of that portion whichis not covered by the hexagon? About the author Ella
Answer: Let, Side of hexagon = 4 Since hexagon is inscribed in Circle so teh diamater of the Circle = Longest diagonal of the hexagon But Hexagon = 6 equilateral triangles of the same side i.e. Diameter = 2*Side of hexagon = 2*4 = 8 Area of Hexagon = 6*(√3/4)*4^2 = 24√3 Area of Circle = πr^2 = 16π Hexagon / Circle = 24√3 / 16π = 3√3 / 2π the final answer is3√3:2π Reply
Answer:
Let, Side of hexagon = 4
Since hexagon is inscribed in Circle so teh diamater of the Circle = Longest diagonal of the hexagon
But Hexagon = 6 equilateral triangles of the same side
i.e. Diameter = 2*Side of hexagon = 2*4 = 8
Area of Hexagon = 6*(√3/4)*4^2 = 24√3
Area of Circle = πr^2 = 16π
Hexagon / Circle = 24√3 / 16π = 3√3 / 2π
the final answer is3√3:2π