In this question, the breadth and area of a rectangular stall is given to us. We have to find it’s length. The stall is in the shape of a rectangle as it’s a rectangular stall. So, to find it’s length using it’s area, we will use the formula required for finding the area of a rectangle.
We know that :-
[tex]\underline{\boxed{\sf Area \: of \: a \: rectangle = Length \times Breadth}}[/tex]
Here,
Area = 29 3/4 sq.m.
Breadth = 3 1/2 m.
Let the length of the stall be “l” m.
Substituting the given values in this formula,
[tex]\leadsto \rm 29 \dfrac{3}{4} = l \times 3 \dfrac{1}{2}[/tex]
Converting the mixed fractions into improper fractions,
[tex]\leadsto\rm \dfrac{119}{4} = l \times \dfrac{7}{2}[/tex]
Answer:
8 1/2m
Step-by-step explanation:
Length=area/breadth=119/4/7/2
=17/2=8 1/2m
Answer :-
To find :-
Solution :-
We know that :-
[tex]\underline{\boxed{\sf Area \: of \: a \: rectangle = Length \times Breadth}}[/tex]
Here,
Substituting the given values in this formula,
[tex]\leadsto \rm 29 \dfrac{3}{4} = l \times 3 \dfrac{1}{2}[/tex]
Converting the mixed fractions into improper fractions,
[tex]\leadsto\rm \dfrac{119}{4} = l \times \dfrac{7}{2}[/tex]
Multiplying l with 7/2,
[tex]\leadsto\rm \dfrac{119}{4} = \dfrac{7l}{2}[/tex]
Transposing 2 from RHS to LHS, changing it’s sign,
[tex]\leadsto\rm \dfrac{119}{4} \times 2 = 7l[/tex]
Reducing the numbers,
[tex]\leadsto\rm \dfrac{119}{2} \times 1 = 7l[/tex]
Multiplying 119/2 with 1,
[tex]\leadsto\rm \dfrac{119}{2} = 7l[/tex]
Transposing 7 from RHS to LHS, changing it’s sign,
[tex]\leadsto\rm \dfrac{119}{2} \div 7 = l[/tex]
The reciprocal of 7 is 1/7, so multiplying 119/2 with 1/7,
[tex]\leadsto\rm \dfrac{119}{2} \times \dfrac{1}{7} = l[/tex]
Reducing the numbers,
[tex]\leadsto\rm \dfrac{17}{2} \times \dfrac{1}{1} = l[/tex]
Multiplying 17/2 with 1/1,
[tex]\leadsto\rm \dfrac{17}{2} = l[/tex]
Converting the improper fraction into mixed fraction,
[tex]\leadsto\overline{\boxed{\rm 8\dfrac{1}{2} \: m= l}}[/tex]
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