A rectangular field is 96m in length and 42m in breadth. A path of uniform width 3m runs immediately inside its boundary. Find the cost of gravelling the path at RS.32 per square meter. About the author Bella
Length of garden =90m Breadth of garden =75m Width of path =5m Outer length =100m(90+5+5) Outer breadth =85m(75+5+5) Area of path = area of outer rectangle – area of inner rectangle ⇒(100⋅85)−(90⋅75) ⇒8500−6750=1750m2 Hence, area of rectangle 1= 1750 m^21 Now, 1hec=2592m2 Area of path in hec=1752592=675 Area of garden in hec=67502592=2.604 Reply
[tex]❥\huge\red{\underline{{\bf A}}}\huge\orange{\underline{{\bf n}}}\huge\green{\underline{{\bf s}}}\huge\blue{\underline{{\bf w}}}\huge\purple{\underline{{\bf e}}}\huge\pink{\underline{{\bf r}}}[/tex] [tex]Length \: of \: garden =90m [/tex] Breadth of garden =75m Width of path =5m Outer length =100m(90+5+5) Outer breadth =85m(75+5+5) Area of path = area of outer rectangle – area of inner rectangle ⇒(100⋅85)−(90⋅75) ⇒8500−6750=1750m2 Hence, area of rectangle 1= 1750 m^21 Now, 1hec=2592m2 Area of path in hec=1752592=675 Area of garden in hec=67502592=2.604 Reply
Length of garden =90m
Breadth of garden =75m
Width of path =5m
Outer length =100m(90+5+5)
Outer breadth =85m(75+5+5)
Area of path = area of outer rectangle – area of inner rectangle
⇒(100⋅85)−(90⋅75) ⇒8500−6750=1750m2
Hence, area of rectangle 1= 1750 m^21 Now,
1hec=2592m2
Area of path in hec=1752592=675
Area of garden in hec=67502592=2.604
[tex]❥\huge\red{\underline{{\bf A}}}\huge\orange{\underline{{\bf n}}}\huge\green{\underline{{\bf s}}}\huge\blue{\underline{{\bf w}}}\huge\purple{\underline{{\bf e}}}\huge\pink{\underline{{\bf r}}}[/tex]
[tex]Length \: of \: garden =90m [/tex]
Breadth of garden =75m
Width of path =5m
Outer length =100m(90+5+5)
Outer breadth =85m(75+5+5)
Area of path = area of outer rectangle – area of inner rectangle
⇒(100⋅85)−(90⋅75) ⇒8500−6750=1750m2
Hence, area of rectangle 1= 1750 m^21 Now,
1hec=2592m2
Area of path in hec=1752592=675
Area of garden in hec=67502592=2.604