a rectangle sheet of paper is 11 1/2 cm long and 10 2/3 cm wide. find its perimeter About the author Raelynn
Answer: Perimeter of rectangle = 2[l+b] [tex]2(11 \times \frac{1}{2} + 10 \times \frac{2}{3} ) \\ 2( \frac{23}{2} + \frac{32}{3} ) \\ 2( \frac{69 + 64}{6} ) \\ 2 \times \frac{133}{6} \\ = \frac{133}{3} [/tex] Reply
Answer:
Perimeter of rectangle = 2[l+b]
[tex]2(11 \times \frac{1}{2} + 10 \times \frac{2}{3} ) \\ 2( \frac{23}{2} + \frac{32}{3} ) \\ 2( \frac{69 + 64}{6} ) \\ 2 \times \frac{133}{6} \\ = \frac{133}{3} [/tex]