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A quadratic polynomial, whose zeros are 5 and -8 is
(a)x^2+13x-40
(b) x^2 + 4x-3
(c)x^2 + 3x – 40
(d)x^2 – 3

By Evelyn

A quadratic polynomial, whose zeros are 5 and -8 is
(a)x^2+13x-40
(b) x^2 + 4x-3
(c)x^2 + 3x – 40
(d)x^2 – 3x + 40​

About the author
Evelyn

14. When two dispalcements represented by
Yo = asin(wt) and y, = b cos(at) are superimposed
the motion is :
1

18. Solve for A and B. when
3
ZA+B=
A
and A-2B
2
7​

2 thoughts on “A quadratic polynomial, whose zeros are 5 and -8 is<br />(a)x^2+13x-40<br /> (b) x^2 + 4x-3<br /> (c)x^2 + 3x – 40<br />(d)x^2 – 3”

  2. Answer:

    c) x² + 3x – 40

    Step-by-step explanation:

    Zeros are given as 5 and -8.

    Finding the sum of Zeros:

    Sum of Zeros = 5 + (-8)

    → Sum of Zeros = -3

    Finding the product of zeros:

    Product of zeros = 5 × (-8)

    → Product of Zeros = -40

    The General formula of Quadratic Polynomial when it’s sum and product of zeros is known can be given as:

    Polynomial = x² – (Sum of Zeros)x + Product of Zeros

    → Quadratic polynomial = x² – (-3)x + (-40)

    → Quadratic polynomial = x² + 3x – 40

    So, Quadratic polynomial = x² + 3x – 40

    KNOW MORE:

    ★ Generally Zeros of a Quadratic polynomial are represented by Alpha and Beta symbols.

    ★ For a Quadratic polynomial of general form ax² + bx + c

    • Sum of Zeros = -b ÷ a
    • Product of zeros = c ÷ a
    Reply

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